How do you solve a predator/prey differential equation?

How do you solve a predator/prey differential equation?

Consider the pair of first-order ordinary differential equations known as the Lotka-Volterra equations, or predator-prey model: dx dt = x – α xy dy dt = – y + β xy . The variables x and y measure the sizes of the prey and predator populations, respectively.

What is ode23 Matlab?

ode23 is an implementation of an explicit Runge-Kutta (2,3) pair of Bogacki and Shampine. It may be more efficient than ode45 at crude tolerances and in the presence of moderate stiffness. ode23 is a single-step solver [1], [2].

How are predator/prey relationships calculated?

The equation for prey can be summed up as: the rate at which new prey is born, minus the rate at which prey is killed off. Looking now at the predator equation we can see that the growth of the predator population is proportional to the amount of times the two populations meet.

What is Rosenzweig MacArthur model?

Rosenzweig-MacArthur predator-prey model is one of such model that presents the advantage of being simple and yet exhibits very rich dynamics. It is mostly used to study bifurcation and chaotic behaviour in predator-prey interactions. Predator growth is proportional to its prey population size or density.

What is the difference between ode45 and ode23?

ode23 is a three-stage, third-order, Runge-Kutta method. ode45 is a six-stage, fifth-order, Runge-Kutta method. ode45 does more work per step than ode23, but can take much larger steps. For differential equations with smooth solutions, ode45 is often more accurate than ode23.

What does ode45 do in Matlab?

ODE45 is usually the function of choice among the ODE solvers. It compares methods of orders four and five to estimate error and determine step size. ODE45 is so accurate that its default behavior is to use its interpolant to provide results at intermediate points.

What are the Volterra prey predator equation?

Equations

1. Lotka-Volterra model of change in prey number in the presence of a predator:
N = prey number prey #
c = 2 r Ve−1 − 1 [N]0[T]0
T = 2 V e – 1 c – 1 ( c – 1 ( K c – 1 ) – ln K ) T 1 = T 1 T 0 ( ( N 0 T 0 ) – 1 ) ( N 0 T 0 ) c – ln ( N 0 T 0 ) ) T 1 = T 1 ( N 0 T 0 – N 0 T 0 )

How do you calculate predation rate?

In the simplest form of the model, the predator is specialized on just one prey species – therefore in the absence of prey, the predator population declines exponentially: dP/dt = -qP where P is the predator population size, and q is the per capita death rate (NB: Symbols vary from book to book!)

What is the ratio of predators to prey?

The prey-to-predator ratio range (1.25:1 to 5.20:1) was only 9% of the potential range.

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